answer:Let's denote the original cost of the scooter as ( C ). According to the problem, Anil made a profit of 25% on the original cost when he sold the scooter. This profit is given as Rs. 1800. Therefore, we can write the profit as: [ text{Profit} = 0.25C = Rs. 1800 ] From this, we can solve for ( C ): [ C = frac{Rs. 1800}{0.25} ] [ C = Rs. 7200 ] Now, we know the cost of each repair as a percentage of the original cost: - First repair: 8% of ( C ) - Second repair: 12% of ( C ) - Third repair: 5% of ( C ) Let's calculate the cost of the third repair: [ text{Third repair cost} = 0.05C ] [ text{Third repair cost} = 0.05 times Rs. 7200 ] [ text{Third repair cost} = Rs. 360 ] Therefore, Anil spent Rs. boxed{360} on the third repair.

answer:To solve this problem, we need to first determine the speed of the train when it crosses the signal pole. Since the train is 300 m long and it takes 18 seconds to pass the signal pole, we can calculate the speed of the train using the formula: Speed = Distance / Time The distance the train covers when passing the signal pole is equal to the length of the train, which is 300 m. The time taken is 18 seconds. So the speed of the train is: Speed = 300 m / 18 s = 16.67 m/s (approximately) Now, to find out how long it takes for the train to cross the platform, we need to consider the combined length of the train and the platform, which is 300 m + 400 m = 700 m. Using the speed we calculated earlier, we can find the time it takes to cross the platform by using the formula: Time = Distance / Speed The distance to be covered is the combined length of the train and the platform, which is 700 m. The speed of the train is 16.67 m/s. So the time taken to cross the platform is: Time = 700 m / 16.67 m/s ≈ 42 seconds Therefore, it takes approximately boxed{42} seconds for the train to cross the platform.

answer:1. **Determine the rate of Petya's clock:** Petya's clock runs fast by 5 minutes every hour. Thus, for each real hour, Petya's clock registers 65 minutes (60 minutes + 5 minutes). To find the ratio of Petya's clock time to actual time: [ text{Rate of Petya's clock} = frac{65 text{ minutes}}{60 text{ minutes}} = frac{13}{12} ] Therefore, Petya's clock runs (frac{13}{12}) times faster than the real clock. 2. **Determine the time passage for Petya's clock:** They agreed to meet at 18:30 according to their own clocks. For Petya: [ 18 , text{hours} , 30 , text{minutes} = 18.5 , text{hours} ] Since Petya's clock runs at (frac{13}{12}) times the real time: [ text{Real time elapsed for Petya} = 18.5 times frac{12}{13} = frac{222}{13} approx 17.08 , text{hours} ] From 12:00 PM to 17.08 hours is: [ 17.08 - 12 = 5.08 , text{hours} approx 5 , text{hours and} , 5 , text{minutes} ] 3. **Determine the rate of Masha's clock:** Masha's clock lags behind by 8 minutes every hour. Thus, for each real hour, Masha's clock only registers 52 minutes (60 minutes - 8 minutes). To find the ratio of Masha's clock time to actual time: [ text{Rate of Masha's clock} = frac{52 text{ minutes}}{60 text{ minutes}} = frac{13}{15} ] Therefore, Masha's clock runs (frac{13}{15}) times slower than the real clock. 4. **Determine the time passage for Masha's clock:** For Masha: [ 18 , text{hours} , 30 , text{minutes} = 18.5 , text{hours} ] Since Masha's clock runs at (frac{13}{15}) times the real time: [ text{Real time elapsed for Masha} = 18.5 times frac{15}{13} = frac{277.5}{13} approx 21.35 , text{hours} ] From 12:00 PM to 21.35 hours is: [ 21.35 - 12 = 9.35 , text{hours} approx 9 , text{hours and} , 21 , text{minutes} ] 5. **Calculate the difference between Petya and Masha's arrival times:** From the calculations: [ text{Time Petya arrives (real time):} , 17.08 , text{hours} ] [ text{Time Masha arrives (real time):} , 21.35 , text{hours} ] The waiting time for Petya: [ text{Masha's arrival} - text{Petya's arrival} = 21.35 , text{hours} - 17.08 , text{hours} approx 4.27 , text{hours} ] Converting the waiting time to hours and minutes: [ 4.27 , text{hours} approx 4 , text{hours and} , 16 , text{minutes} ] # Conclusion: [ boxed{4 , text{hours and} , 16 , text{minutes}} ]

answer:Tonya spends 15 on each doll for her younger sister and buys 4 dolls. So, the total amount spent on her younger sister is: 4 dolls * 15/doll = 60 Since Tonya wants to spend the exact same amount on her older sister, she has 60 to spend on lego sets that cost 20 each. To find out how many lego sets she can buy, we divide the total amount she can spend by the cost of each lego set: 60 / 20/lego set = 3 lego sets Therefore, Tonya buys boxed{3} lego sets for her older sister.