answer:The average GPA for 6th graders is 93. The 7th graders' average GPA is 2 more than the 6th graders, so it is 93 + 2 = 95. The 8th graders' average GPA is 91. To find the average GPA for the school, we need to find the average of all three grades. To do that, we add up the GPAs for each grade and divide by the number of grades. So the average GPA for the school is (93 + 95 + 91) / 3 = 93. 93 The answer is: 93

answer:We want to find the value of X in the given situation. The temperature at a particular time t is given by the equation -t^2 + 12t + 50. We are looking for the largest t value at which the temperature was exactly X degrees. To find this value of t, we can set up the equation and solve for t. -t^2 + 12t + 50 = X We are given that the largest t value is 9, so we can substitute it into the equation: -9^2 + 12(9) + 50 = X Simplifying the equation, we get: -81 + 108 + 50 = X 77 = X The value of X is 77. The answer is: 77

answer:Adding the two equations, we get (x - y) + (x + y) = 6 + 12, which simplifies to 2x = 18. Dividing both sides by 2, we find that x = 9. Substituting this value into the second equation, we have 9 + y = 12. Solving for y, we get y = boxed{3}. The answer is: 3

answer:: x + y = 6 x^2 - y^2 = X To find the value of x - y, we can solve these equations simultaneously. We can rewrite the second equation as a difference of squares: (x + y)(x - y) = X We can substitute the value of x + y from the first equation into the second equation: 6(x - y) = X Now, we can solve for x - y by dividing both sides of the equation by 6: x - y = frac{X}{6} Given that the value of x - y is 2, we can substitute it into the equation: 2 = frac{X}{6} Multiplying both sides of the equation by 6 to eliminate the fraction, we get: 12 = X The value of X is 12. The answer is: 12